Emu8086 code
Without that prefix, mov al, StuId would fetch the values from the data segment.
EMU8086 CODE CODE
This tells the CPU to fetch the elements from your StuId array in the code segment. Mov al, cs:StuId uses a cs: segment override prefix. Mov al, cs:StuId <<<< cs: segment override prefix Since all of this is about learning assembly language, why don't you try them all! data segment Your copy can remain as before.Īlso possible would be to combine both copies in one loop, or not copy to 3500h at all, if all you need is the final array at 3600h. Copy the above code to emu8086 source editor, and press F5 key to compile and load it in the emulator. What I have tried: Tried using the assembly code emitted by Visual Studio but it is 32-bit and won't work. An alternative solution has the array stored in the code segment and then copies its elements to offset 3500h of the data segment. Does anyone if it is possible to convert C source code into 16-bit 8086 assembly (for use with EMU8086) Thanks. That's all I could understand and find for now.ĭepending on the assembler used, and I am not familiar with emu8086 as an assembler but more as an emulator, the assembler needs to be told where the starting point or entry point of the program is.If what you want is to have those initialized arrays at the specified offsets within the data segment, and ORG doesn't work for you, then just bridge the gap by filling the void with zeroes: data segmentĪ drawback of the above code is that your program gets very big.
EMU8086 CODE SOFTWARE
By the way, the DX resets every time mov dl, executes. When it comes to code writing and producing new software with a processor so closely related to 8086, this emulation is superior to other alternatives. new location is: c:emu8086.io Default code templates can be customised in c:emu8086inc. The printing is as it is because of this line add dx,48d, so that's why all it prints is 00000. All devices must be recompiled with new location of IO file. (I can't find a way to copy from the emulator, so I'm gonna paste a screenshot)Īnd here are the values of the array NIZA in the emulator before and after executing this lines of code: When the program starts there are these few lines that execute, that don't in the one where I include start: and end start: The program runs as it supposed to and the output is all the elements of the array printed.Ģ) start: and end start not included (the same code,but the labels excluded):.I tried it with and without adding the labels and here is the results: assembly for printing an array of the integers 1-5 I was writing a program for printing the numbers 1-5 which are contained in an array. So my question is are this labels necessary for the execution, does the code access some addresses that is not supposed to when these labels are excluded and are these labels that surround the executing code the same as start(='') of main() in java class? include emu8086.inc //Macro declaration ORG 100h PRINT ‘Hello World’ GOTOXY 10, 5 PUTC 65 // 65 is an ASCII code for ‘A’ PUTC ‘B’ RET //return to the operating system. To print out characters you use DOS interrupt calls (INT 21H). ( end start) (labels that surround the executing code)? Specifically the code you used starting with an ORiGin metainstruction denotes the writing of a binary '.com' executable (by default located at adrress 0x100). I don't have much experience in 8086 assembly and I like to know what happens in the program if you don't write the starting label ( start:) and the end of that label If after running the program there are more unsatisfied results you should review and fix your code again until you reach your goal. include emu8086.inc ORG 100h MOV AL, 1 CMP AL, 5 JB label1 PRINT AL is not below 5 JMP exit label1: PRINT AL is below 5 exit: RET : JBE label: Short Jump if first operand is Below or Equal to second operand (as set by CMP instruction).